Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $\mathrm{F}$ is the force…
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $\mathrm{F}$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge on an electron)
Two positive ions each carrying a charge $q$ are kept at a distance $\mathrm{d}$, then it is found that force of repulsion between them is
$\begin{aligned}
\mathrm{F} & =\frac{\mathrm{kqq}}{\mathrm{d}^2} \\
& =\frac{1}{4 \pi \varepsilon_0} \frac{q q}{\mathrm{~d}^2}
\end{aligned}$
where
$\begin{array}{ll}
\text { where } & \mathrm{q}=\mathrm{ne} \\
\therefore & \mathrm{F}=\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{n}^2 \mathrm{e}^2}{\mathrm{~d}_2} \\
\Rightarrow & \mathrm{n}=\sqrt{\frac{4 \pi \varepsilon_0 \mathrm{Fd}_2}{\mathrm{e}^2}}
\end{array}$