Two points are located at a distance of $10 \mathrm{~m}$ and $15 \mathrm{~m}$ from the source of oscillation…

Two points are located at a distance of $10 \mathrm{~m}$ and $15 \mathrm{~m}$ from the source of oscillation. The period of oscillation is $0.05 \mathrm{sec}$ and the velocity of the wave is $300 \mathrm{~m} / \mathrm{sec}$. What is the phase difference between the oscillations of two points?
  1. $\frac{\pi}{6}$
  2. $\frac{\pi}{3}$
  3. $\frac{2 \pi}{3}$
  4. $\pi$

Solution

Phase difference $\phi=\frac{2 \pi}{\lambda} \times$ path difference $\begin{aligned} & =\frac{2 \pi}{15} \times(15-10) \quad\{\lambda=v T=300 \times 0.05 \mathrm{~m}\} \\ & =\frac{2 \pi}{5} \end{aligned}$

Asked in: NEET 2008 (Mains)

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