Two points $P$ and $Q$ are maintained at the potentials of $10 \mathrm{~V}$ and $-4 \mathrm{~V}$…

Two points $P$ and $Q$ are maintained at the potentials of $10 \mathrm{~V}$ and $-4 \mathrm{~V}$ respectively. The work done in moving 100 electrons from $P$ to $Q$ is
  1. $-19 \times 10^{-17} \mathrm{~J}$
  2. $9.60 \times 10^{-17} \mathrm{~J}$
  3. $-2.24 \times 10^{-16} \mathrm{~J}$
  4. $2.24 \times 10^{-16} \mathrm{~J}$

Solution

$ \begin{aligned} & W=Q d V=Q\left(V_q-V_P\right)=-100 \times\left(1.6 \times 10^{-19}\right) \times(-4-10) \\ & =+100 \times 1.6 \times 10^{-19} \times 14=+2.2410^{-16} \mathrm{~J} \end{aligned} $

Asked in: JEE Main 2009

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