Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the…

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 km s-1 is given to the 5 kg mass at an angle of 60° to the line joining the masses. The velocity of the 10 kg mass just after the impulse will be 
 
  1. 23 m s-1
  2. 13 m s-1
  3. 2 m s-1
  4. zero

Solution

Apply impulse equation, along string



Impulse = Δp
10 × 12=10 + 5v

v=13m s-1

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