Two-point charges $+Q$ and $+q$ repel each other with a force of $100 \mathrm{~N}$. Keeping the distance…

Two-point charges $+Q$ and $+q$ repel each other with a force of $100 \mathrm{~N}$. Keeping the distance between them unchanged, if $Q$ is increased by $10 \%$ and $q$ is decreased by $q$ the force of repulsion between them will.
  1. decrease by $10 \mathrm{~N}$
  2. decrease by $1 \mathrm{~N}$
  3. increase by $10 \mathrm{~N}$
  4. remain same

Solution

Given, $100 \mathrm{~N}=\frac{k Q q}{r^2}$ and $F=\frac{k(1.1 Q)(0.9 q)}{r^2}$ Taking the ratio of above two equations: $F=99$

Asked in: MHT CET 2022 (10 Aug Shift 1)

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