Two point charges $A$ and $B$, having charges $+Q$ and $-Q$ respectively, are placed at a certain distance apart and the force acting between them is $F$. If $25\%$ charge of $A$ is transferred to $B$, then the force between the charges becomes

Question

Aicharya · Accepted Answer

F = K Q 2 r 2 After transferring 25 % of charge, q 1 = 3 Q 4 and q 2 = - 3 Q 4 F 1 = 9 16 K Q 2 r 2 = 9 16 F

Two point charges $A$ and $B$, having charges $+Q$ and $-Q$ respectively, are placed at a certain distance…

Solution