Two point charges $-4 \mu c$ and $4 \mu c$, constituting an electric dipole, are placed at $(-9,0,0)…

Two point charges $-4 \mu c$ and $4 \mu c$, constituting an electric dipole, are placed at $(-9,0,0) \mathrm{cm}$ and $(9,0,0) \mathrm{cm}$ in a uniform electric field of strength $10^4 \mathrm{NC}^{-1}$. The work done on the dipole in rotating it from the equilibrium through $180^{\circ}$ is :
  1. 18.4 mJ
  2. 14.4 mJ
  3. 12.4 mJ
  4. 16.4 mJ

Solution

$\begin{aligned} & \mathrm{U}=-\mathrm{PE} \cos \theta \\ & \mathrm{w}_{\mathrm{ext}}=\Delta \mathrm{U}=\mathrm{U}_{\mathrm{f}}-\mathrm{U}_{\mathrm{i}}=-\mathrm{PE} \cos 180^{\circ}+\mathrm{PE} \cos 0^{\circ} \\ & \mathrm{w}_{\mathrm{ext}}=2 \mathrm{PE} \\ & =2 \times\left(4 \times 10^{-6}\right)(18) \times 10^4 \\ & =144 \times 10^{-2} \\ & =14.4 \mathrm{~mJ}\end{aligned}$

Asked in: JEE Main 2025 (23 Jan Shift 2)

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