Two players, P 1 and P 2 , play a game against each other. In every round of the game, each player rolls a…

Two players, P1 and P2, play a game against each other. In every round of the game, each player rolls a fair die once, where the six faces of the die have six distinct numbers. Let x and y denote the readings on the die rolled by P1 and P2, respectively. If x>y, then P1 scores 5 points and P2 scores 0 point. If x=y, then each player scores 2 points. If x<y, then P1 scores 0 point and P2 scores 5 points. Let Xi and Yi be the total scores of P1 and P2, respectively, after playing the ith round.

  List-I   List-II
I Probability of X2Y2 is P 38
II Probability of X2>Y2 is Q 1116
III Probability of X3=Y3 is R 516
IV Probability of X3>Y3 is S 355864
    T 77432

The correct option is:

  1. IQ;IIR;IIIT;IVS
  2. IQ;IIR;IIIT;IVT
  3. IP;IIR;IIIQ;IVS
  4. IP;IIR;IIIQ;IVT

Solution

Given,

P(draw in 1 round)=636=16

P(win in 1 round) =121-16=512

P(loss in 1 round) =512

Now finding the probability of all we get,PX2>Y2=P10,0+P7,2=512×512+512×16×2=45144=516R

PX2=Y2=P5,5+P4,4=512×512×2+16×16=25+272=38

PX2Y2=516+38=1116Q

PX3=Y3=P6,6+P7,7=16×6×6+512×16×512×6=2432+75432=77432T

PX3>Y3=121-77432=355864S

Asked in: JEE Advanced 2022 (Paper 1)

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