Two plane polarized light waves combine at a certain point whose electric field components are…
$\begin{aligned} & \mathrm{E}_1=\mathrm{E}_0 \sin \omega \mathrm{t} \\ & \mathrm{E}_2=\mathrm{E}_0 \sin \left(\omega \mathrm{t}+\frac{\pi}{3}\right)\end{aligned}$
Find the amplitude of the resultant wave.
- 0.9 E
- $\mathrm{E}_0$
- $1.7 \mathrm{E}_0$
- $3.4 \mathrm{E}_0$
Solution
$\mathrm{E}=\sqrt{2 \mathrm{E}_0^2+\mathrm{E}_0^2}=\sqrt{3} \mathrm{E}_0=1.73 \mathrm{E}_0$
Asked in: JEE Main 2025 (07 Apr Shift 1)