Two periodic waves of amplitudes $a$ and $b$ pass through a region at the same time in the same direction.…
Two periodic waves of amplitudes $a$ and $b$ pass through a region at the same time in the same direction. If $a > b$, the difference in the maximum and minimum possible amplitudes is
$a + b$
$a - b$
$2a$
$2b$
Solution
$A_{\text{max}} = a + b$ and $A_{\text{min}} = a - b$
$\therefore A_{\text{max}} - A_{\text{min}} = 2b$