Two particles of masses m 1 , m 2 move with initial velocities u 1 and u 2 . On collision, one of the…

Two particles of masses m1, m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be v1 and v2 then we must have:

  1. m12u1+m22u2-ε=m12v1+m22v2
  2. 12m1u12+12m2u22=12m1v12+12m2v22-ε
  3. 12m1u12+12m2u22-ε=12m1v12+12m2v22
  4. 1 2 m 2 u 1 2  +  1 2 m 1 u 1 2 + ε =  1 2 m 2 v 1 2  +  1 2 m 1 v 1 2

Solution

From conservation of energy initial total energy
Ei=12m1u12+12m2u22
After collision total final energy
Ef=12m1v12+12m2v22+ε


12m1u12+12m2u22=12m1v12+12m2v22+ε
12m1u12+12m2u22-ε=12m1v12+12m2v22

Asked in: NEET 2015 (Phase 1)

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