Two particles of masses in the ratio $1: 2$ are placed along a vertical line. The lighter particle is raised through a height of $9 \mathrm{~cm}$. To raise the centre of mass of the system by 2 $\mathrm{cm}$, the heavier particle should be

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Aicharya · Accepted Answer

Let initially particles are at origin, their masses are $m$ and $2 m$.

$ \begin{aligned} 2 & =\frac{m \times 9+2 m \times y_2}{3 m} \\ 2 & =\frac{9+2 y_2}{3} \\ y_2 & =-1.5 \mathrm{~cm} \end{aligned} $ So, second particle must be moved $1.5 \mathrm{~cm}$ downward

Two particles of masses in the ratio $1: 2$ are placed along a vertical line. The lighter particle is raised…

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