Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational…

Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational attraction. The speed of each particle will be :
  1. Gm2r
  2. 4Gmr
  3. Gmr
  4. Gm4r

Solution

Let speed of both the particles be v.

Then, gravitational force between the particles will provide the required centripetal force.

Therefore,

Gmm2r2=mv2r

⇒v=Gm4r

Asked in: JEE Main 2023 (29 Jan Shift 1)

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