Two particles of charges 4 nC and Q are kept in air with a separation of 10 cm between them. If the electrostatic potential energy of the system is $1.8 \mu \mathrm{~J}$. Then $\mathrm{Q}=$

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Aicharya · Accepted Answer

$\begin{aligned} & U=1.8 \mu J, r=10 \mathrm{~cm} \\ & \therefore U=\frac{\mathrm{kQ}_1 Q_2}{r} \\ & \Rightarrow 1.8 \times 10^{-6}=\frac{9 \times 10^9 \times 4 \times 10^{-9} \times Q}{10 \times 10^{-2}} \\ & \therefore \quad Q=5 \mathrm{nC}\end{aligned}$

Two particles of charges 4 nC and Q are kept in air with a separation of 10 cm between them. If the…

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