Two particles move at right angle to each other. Their de Broglie wavelengths are λ 1 and λ 2…

Two particles move at right angle to each other. Their de Broglie wavelengths are λ1 and λ2 respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength λ of the final particle, is given by:
  1. 2λ=1λ1+1λ2
  2. λ=λ1+λ22
  3. λ=λ1λ2
  4. 1λ2=1λ12+1λ22

Solution

P1=hλ1i^,    P2=hλ2j^
P=P1+P2=hλ1i^+hλ2j^
P=h1λ12+1λ22
hλ=h1λ12+1λ22
1λ2=1λ12+1λ22

Asked in: JEE Main 2019 (08 Apr Shift 1)

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