Two particles executing SHM along a straight line have same amplitude 'A' and time period ' $T$ '. At $t=0$,…

Two particles executing SHM along a straight line have same amplitude 'A' and time period ' $T$ '. At $t=0$, one particle is at a displacement $+A$ and another is at a displacement $-\frac{A}{2}$ and they are approaching towards each other. They cross each other after a time.
  1. $\frac{T}{3}$
  2. $\frac{T}{4}$
  3. $\frac{5 T}{6}$
  4. $\frac{T}{6}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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