Two open organ pipes, sounded simultaneously, are given 5 beats per second between the fundamentals. If the shorter pipe is $1.10 ext{ m}$ long, the length of the longer pipe is (Take, velocity of sound in air $= 340 ext{ m s}^{-1}$) [AMU 2012]

Question

Two open organ pipes, sounded simultaneously, are given 5 beats per second between the fundamentals. If the shorter pipe is $1.10	ext{ m}$ long, the length of the longer pipe is (Take, velocity of sound in air $= 340	ext{ m s}^{-1}$) [AMU 2012]

Aicharya · Accepted Answer

Here, $n_1 - n_2 = 5$ $\frac{v}{2l_1} - \frac{v}{2l_2} = 5$ $\left(\because n = \frac{v}{2l}ight)$ $\Rightarrow \frac{1}{l_1} - \frac{1}{l_2} = \frac{5 	imes 2}{v}$ $\Rightarrow \frac{1}{1.10} - \frac{1}{l_2} = \frac{10}{340}$

Two open organ pipes, sounded simultaneously, are given 5 beats per second between the fundamentals. If the…

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