Two monochromatic light beams have intensities in the ratio 1:9. An interference pattern is obtained by…

Two monochromatic light beams have intensities in the ratio 1:9. An interference pattern is obtained by these beams. The ratio of the intensities of maximum to minimum is
  1. $8: 1$
  2. $9: 1$
  3. $3: 1$
  4. $4: 1$

Solution

$\frac{I_{\max }}{I_{\min }}=\frac{\left(\sqrt{I_1}+\sqrt{I_2}\right)^2}{\left(\sqrt{I_1}-\sqrt{I_2}\right)^2} \Rightarrow \frac{(4)^2}{(2)^2} \Rightarrow \frac{16}{4}=4$

Asked in: JEE Main 2025 (03 Apr Shift 2)

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