Two moles of helium gas $\left(\gamma=\frac{5}{3}\right)$ at $27^{\circ} \mathrm{C}$ is expanded at constant…

Two moles of helium gas $\left(\gamma=\frac{5}{3}\right)$ at $27^{\circ} \mathrm{C}$ is expanded at constant pressure until its volume is doubled. Then it undergoes an adiabatic change until the temperature returns to its initial value. The work done during adiabatic process is (universal gas constant $=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ )
  1. $7470 \mathrm{~J}$
  2. $7070 \mathrm{~J}$
  3. $4770 \mathrm{~J}$
  4. $4077 \mathrm{~J}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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