Two metal pieces having a potential difference of $800 \mathrm{~V}$ are $0.02 \mathrm{~m}$ apart horizontally. A particle of mass $1.96 imes 10^{-15} \mathrm{~kg}$ is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is

Question

Two metal pieces having a potential difference of $800 \mathrm{~V}$ are $0.02 \mathrm{~m}$ apart horizontally. A particle of mass $1.96 	imes 10^{-15} \mathrm{~kg}$ is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is

Aicharya · Accepted Answer

For equilibrium $m g=q E$ $\begin{aligned} & \therefore 1.96 \times 10^{-15} \times 9.8=q \times\left(\frac{800}{0.02}\right) \ & \Rightarrow q=\frac{1.96 \times 10^{-15} \times 9.8 \times 0.02}{800} \ & \Rightarrow n \times 1.6 \times 10^{-19}=\frac{1.96 \times 10^{-15} \times 9.8 \times 0.02}{800} \Rightarrow n=3 . \end{aligned}$ ^

Two metal pieces having a potential difference of $800 \mathrm{~V}$ are $0.02 \mathrm{~m}$ apart…

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