Two masses m 1 = 5   kg and m 2 = 10   kg , connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0 . 15 . The minimum weight m that should be put on top of m 2 to stop the motion is:

Question

Two masses m 1 = 5 &#160; kg and m 2 = 10 &#160; kg , connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0 . 15 . The minimum weight m that should be put on top of m 2 to stop the motion is:

Aicharya · Accepted Answer

T = 5 g &#8658; &#956; 10 + m &#8805; 5 g &#8658; 10 + m &#8805; 5 0.15 &#8658; m &#8805; 23.33 &#160; k g &#8658; m = 27.3 &#160; kg .

Two masses m 1 = 5   kg and m 2 = 10   kg , connected by an inextensible string over a…

Solution

Two masses m 1 = 5 &#160; kg and m 2 = 10 &#160; kg , connected by an inextensible string over a…

Solution

Two masses m 1 = 5 kg and m 2 = 10 kg , connected by an inextensible string over a…