Two masses m 1 and m 2 are connected by a string of length l . They are held in a horizontal plane at a…

Two masses m1 and m2 are connected by a string of length l. They are held in a horizontal plane at a height H above two heavy plates A and B made of different materials placed on the floor. Initially, the distance between the two masses is a<l. When the masses are released they fall freely and collide with the plates simultaneously. The coefficient of restitution for the collision of the first ball-plate pair is 0.8 and for the second ball-plate pair is 0.4. The time after the collision when the string becomes taut is

  1. t=52l2-a22gH
  2. t=54l2-a22gH
  3. t=52la2gH
  4. t=54la2gH

Solution

The string will become taut when

h1-h2=l2-a2

h1=0.8vt-12gt2

h2=0.4vt-12gt2

h1-h2=0.4vt

0.4vt=l2-a2,  where v=2gH

t=52l2-a22gH

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