Two long wires carrying current is $8 \mathrm{~A}$ and $6 \mathrm{~A}$ along $\mathrm{x}$ axes and…

Two long wires carrying current is $8 \mathrm{~A}$ and $6 \mathrm{~A}$ along $\mathrm{x}$ axes and $\mathrm{y}$ axes respectively. The magnetic field at the point $(2 \hat{i}+4 \hat{j})$ is (Take $\mu_{\mathrm{o}}=4 \pi \times 10^{-7}$ SI unit)
  1. $1 \times 10^{-6} \mathrm{~T}$
  2. $2 \times 10^{-6} \mathrm{~T}$
  3. $1 \times 10^{-7} \mathrm{~T}$
  4. $2 \times 10^{-7} \mathrm{~T}$

Solution


We have $\mathrm{B}_{\mathrm{P}}=\frac{\mu_0 \mathrm{i}_1}{2 \pi \mathrm{r}_1} \otimes+\frac{\mu_0 \mathrm{i}_2}{2 \pi \mathrm{r}_2} \odot$ $\begin{aligned} & =2 \times 10^{-7}\left(\frac{6}{2}-\frac{8}{4}\right) \otimes \\ & =2 \times 10^{-7}(3-2) \otimes\end{aligned}$ $=2 \times 10^{-7} \mathrm{~T}$

Asked in: AP EAMCET 2022 (08 Jul Shift 1)

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