Two long straight parallel conductors $10 \mathrm{~cm}$ apart, carry equal currents of magnitude $3…

Two long straight parallel conductors $10 \mathrm{~cm}$ apart, carry equal currents of magnitude $3 \mathrm{~A}$ in the same direction. Then, the magnetic induction at a point midway between them is
  1. $2 \times 10^{-5} \mathrm{~T}$
  2. $3 \times 10^{-5} \mathrm{~T}$
  3. zero
  4. $4 \times 10^{-5} \mathrm{~T}$

Solution


At the mid point of two conductors, the magnetic induction. $B_1=B_2=B$ and $\vec{B}_1$ is anti $\|^{\mathrm{r}}$ to $\vec{B}_2$. Therefore, the net magnetic induction due to two wire at the mid points is $B_{\mathrm{N}}=B_1-B_2=0$

Asked in: AP EAMCET 2015

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