Two long parallel wires $X$ and $Y$, separated by a distance of 6 cm , carry currents of 5A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is $x \times 10^{-5} \mathrm{~T}$. The value of $x$ is__________. Take permeability of free space as $\mu_0=4 \pi \times 10^{-7} \mathrm{SI}$ units.

Question

Aicharya · Accepted Answer

$\begin{aligned} & B=\frac{\mu_0(5)}{2 \pi 	imes.01}-\frac{\mu_0 4}{2 \pi 	imes 0.04} \ & =-\frac{100 \mu_0}{4 \pi} \ & =-100 	imes 10^{-7} \ & =-1 	imes 10^{-5} \mathrm{~T}\end{aligned}$

Two long parallel wires $X$ and $Y$, separated by a distance of 6 cm , carry currents of 5A and 4A,…

Solution