Two lone pairs of electrons and two bond pairs of electrons are present in

1. $\mathrm{BF}_3$
2. $\mathrm{NH}_3$
3. $\mathrm{H}_2 \mathrm{O}$
4. $\mathrm{CO}_2$

Solution

In $\mathrm{H}_2 \mathrm{O}$, two lone pair and two bond pair of $\mathrm{e}^{-\mathrm{s}}$ are present

Asked in: MHT CET 2022 (07 Aug Shift 1)

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