Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference…

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is $V$. The potential difference between the points A and B (shown in the figure) is :

1. $\frac{1}{4} \mathrm{~V}$
2. $\frac{2}{5} \mathrm{~V}$
3. $\frac{3}{4} \mathrm{~V}$
4. 1 V

Solution

$\begin{aligned} & \text { Using } \Delta V=E(\Delta d) \\ & V=E(10) \\ & V_{A B}=E \cdot 4=\frac{V}{10} \times 4=\frac{2 V}{5}\end{aligned}$

Asked in: JEE Main 2025 (02 Apr Shift 2)

Practice more Electrostatics questions on Aicharya