Two interior angles of a triangle are $40^{\circ}$ and $70^{\circ}$. Exterior angle of the third vertex is

Two interior angles of a triangle are $40^{\circ}$ and $70^{\circ}$. Exterior angle of the third vertex is
  1. $110^{\circ}$
  2. $70^{\circ}$
  3. $40^{\circ}$
  4. $180^{\circ}$

Solution

Exterior $= 40 + 70 = 110^{\circ}$.

Asked in: MH-SSC-9

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