Two insulated charged metalic sphere $P$ and $Q$ have their centres separated by a distance of $60…

Two insulated charged metalic sphere $P$ and $Q$ have their centres separated by a distance of $60 \mathrm{~cm}$. The radii of $P$ and $Q$ are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is $3.2 \times 10^{-7} \mathrm{C}$ is
  1. $5.2 \times 10^{-4} N$
  2. $2.5 \times 10^{-3} N$
  3. $1.5 \times 10^{-3} N$
  4. $3.5 \times 10^{-4} N$

Solution

Here $q_{1}=q_{2}=3.2 \times 10^{-7} \mathrm{C}, r=60 \mathrm{~cm}$
$=0.6 \mathrm{~m}$
Electrostatic force, $F=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}}$
$=\frac{9 \times 10^{9}\left(3.2 \times 10^{-7}\right)^{2}}{(0.6)^{2}}=2.56 \times 10^{-3} \mathrm{~N}$ ~

Asked in: JEE Mains - Electrostatics - Test 1

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