Two incident radiations having energies two times and ten times of the work function of a metal surface,…
Two incident radiations having energies two times and ten times of the work function of a metal surface, produce photoelectric effect. The ratio of maximum velocities of emitted photo electrons respectively is
$3: 2$
$1: 3$
$2: 3$
$1: 2$
Solution
$\frac{1}{2} m v_{1}^{2}=2 \phi_{0}-\phi_{0}$
$\frac{1}{2} m v_{2}^{2}=10 \phi_{0}-\phi_{0}$
$\frac{v_{1}^{2}}{v_{2}^{2}}=\frac{1}{9}$
$\therefore \frac{v_{1}}{v_{2}}=\frac{1}{3}$