Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each…
Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with north-pole of one touching south-pole of the other, then the magnetic moment of the system is
$\mathrm{ml}$
$2 \mathrm{ml}$
$\sqrt{2} \mathrm{ml}$
$\mathrm{ml} / 2$
Solution
Here, distance between two poles $=\sqrt{2} 1$
Hence, $\mathrm{M}=\mathrm{m} \times \sqrt{2} \mathrm{l}=\sqrt{2} \mathrm{ml}$