Two identical symmetric double convex lenses of focal length $f$ are cut into two equal parts $L_1, L_2$ by $A B$ plane and $L_3, L_4$ by $X Y$ plane as shown in figure respectively. The ratio of focal lengths of lenses $L_1$ and $L_3$ is

Question

Aicharya · Accepted Answer

so $\frac{f_1}{f_3}=1: 2$

Two identical symmetric double convex lenses of focal length $f$ are cut into two equal parts $L_1, L_2$ by…

Solution