Two identical strings $A$ and $B$ are stretched at tensions $T_A$ and $T_B$. A tuning fork is used to set…
Two identical strings $A$ and $B$ are stretched at tensions $T_A$ and $T_B$. A tuning fork is used to set them in vibration. $A$ vibrates in its fundamental mode and $B$ in its second harmonic mode, then
$T_A = 2T_B$
$T_A = 4T_B$
$2T_A = T_B$
$4T_A = T_B$
Solution
Given, $\frac{v_A}{2l} = 2 \left(\frac{v_B}{2l}\right)$ or $v_A = 2v_B$ but $v \propto \sqrt{T}$
$\therefore T_A = 4T_B$