Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the…

Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers is 150 cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x20 kg m2, where the value of x is

Solution

Using parallel axis theorem, we can write total moment of inertia as, I=25mR2+md2×2

I=225×2×122+2×342=5320 kg m2

Therefore, x=53.

Asked in: JEE Main 2024 (31 Jan Shift 2)

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