Two identical photocathodes receive light of frequencies $\mathrm{f}_1$ and $\mathrm{f}_2$. If the…
- $v_1^2-v_2^2=\frac{2 h}{m}\left(f_1-f_2\right)$
- $v_1+v_2=\left[\frac{2 h}{m}\left(f_1+f_2\right)\right]^{1 / 2}$
- $v_1^2+v_2^2=\frac{2 h}{m}\left(f_1+f_2\right)$
- $\mathrm{v}_1-\mathrm{v}_2=\left[\frac{2 h}{\mathrm{~m}}\left(\mathrm{f}_1-\mathrm{f}_2\right)\right]^{1 / 2}$
Solution
Asked in: JEE Main 2003
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