Two identical long conducting wires A O B and C O D are placed at right angle to each other, with one above…

Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that ‘ O ’ is their common point for the two. The wires carry I1 and I2 currents, respectively. Point ‘ I ’ is lying at distance ‘ d ’ from ‘ O ’ along a direction perpendicular to the plane containing the wires. The magnetic field at the point ‘ P ’ will be:
  1. μ02πdI1I2
  2. μ02πdI1+I2
  3. μ02πdI12-I22
  4. μ02πdI12+I221/2

Solution


B due to wire 1 B1=μ0i12πdi^
B due to wire 2 B2=μ0i22πd-j^
Bnet=μ02πd i12+i22

Asked in: NEET 2014

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