Two identical charged spheres suspended from a common point by two massless strings of lengths l , are…

Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d( dl ) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity υ. Then υ varies as a function of the distance x between the spheres, as
  1. vx12
  2. vx
  3. vx-12
  4. vx-1

Solution


sinθ= θ=x2l, cosθ1
fecosθ=mgsin​θ
fe=mg.x2l
kq2x2=mgx2l
kq2=mg2lx3
qx32
dqdt32 x12.dxdt
x12.v=constant
vx-12

Asked in: NEET 2016 (Phase 1)

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