Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
$0.75 \mathrm{~A}$
zero
$0.25 \mathrm{~A}$
$0.5 \mathrm{~A}$
Solution
Here in circuit $D_1$ is forward bias and $D_2$ is reverse bias. Current will flow only in diode $D_1$
The current supplied by the battery
$i=\frac{5}{10}=0.5 \mathrm{~A}$