Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is
zero
0.25 A
0.50 A
$\quad 0.75 \mathrm{~A}$
Solution
In given circuit, the diode $\mathrm{D}_2$ is connected in reverse bias. Hence, no current flows through $40 \Omega$ resistor.
$\therefore \quad \mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{10}{40}=0.25 \mathrm{~A}$
.