Two gases A and B are at absolute temperatures $360 \mathrm{~K}$ and $420 \mathrm{~K}$ respectively. The…
Two gases A and B are at absolute temperatures $360 \mathrm{~K}$ and $420 \mathrm{~K}$ respectively. The ratio of average kinetic energy of the molecules of gas B to that of gas A is
$6: 7$
$\sqrt{7}: \sqrt{6}$
$7: 6$
$49: 36$
Solution
The mean kinetic energy $\frac{1}{2} \mathrm{~m}<\mathrm{v}>^2$ of the gas molecule is proportional to the temperature $\mathrm{T}$.
$\frac{\mathrm{K}_{\mathrm{B}}}{\mathrm{K}_{\mathrm{A}}}=\frac{\mathrm{T}_{\mathrm{B}}}{\mathrm{T}_{\mathrm{A}}}=\frac{420}{360}=\frac{7}{6}$