Two equally charged metal spheres A and B repel each other with a force of 4 × 10 - 5   N . Another identical uncharged sphere C is touched to A and then placed at the mid point of the line joining the spheres A and B . The net electric force on the sphere C is

Question

Two equally charged metal spheres A and B repel each other with a force of 4 &#215; 10 - 5 &#160; N . Another identical uncharged sphere C is touched to A and then placed at the mid point of the line joining the spheres A and B . The net electric force on the sphere C is

Aicharya · Accepted Answer

Let us suppose that charge on both spheres is, $q$ and when it touches with the uncharged sphere then charge distributed in order of $\frac{q}{2}$ each $A & B$ ,

Before-

$F = K \frac{q^{2}}{r^{2}} = 4 \times 10^{- 5} N$

after-

$F_{A C} = K \frac{{\frac{q}{4}}^{2}}{{\frac{r}{4}}^{2}} = K \frac{q^{2}}{r^{2}} & F_{B C} = K \frac{\frac{q^{2}}{2}}{{\frac{r}{4}}^{2}} = K \frac{2 q^{2}}{r^{2}} F_{C} = F_{B C} - F_{A C} = K \frac{q^{2}}{r^{2}} = 4 \times 10^{- 5} N$

From $C$ to $A$

Two equally charged metal spheres A and B repel each other with a force of 4 × 10 - 5   N .…

Solution

Two equally charged metal spheres A and B repel each other with a force of 4 &#215; 10 - 5 &#160; N .…

Solution

Two equally charged metal spheres A and B repel each other with a force of 4 × 10 - 5 N .…