
Two equal and op po site forces each Fact on a rod of uniform cross-sectional area a as shown in the figure.…

- $\frac{F \sin \theta \cos \theta}{a}$
- $\frac{F \sin \theta}{a}$
- $\frac{F \cos \theta}{a}$
- $\frac{F \sin ^2 \theta}{a}$
Solution

Shearing stress $ \begin{aligned} & =-\frac{F \sin \theta}{a_x} \\ & =-\frac{F}{a} \sin \theta \cos \theta \end{aligned} $ Magnitude of shearing stress $ =\frac{F}{a} \sin \theta \cos \theta $
Asked in: AP EAMCET 2018 (22 Apr Shift 1)
Practice more Mechanical Properties of Solids questions on Aicharya