Two electric circuits $A$ and $B$ are shown in the figure. The ratio of power factor of circuit $B$ to that…

Two electric circuits $A$ and $B$ are shown in the figure. The ratio of power factor of circuit $B$ to that of circuit $A$ is
  1. $\sqrt{3}: 2$
  2. $\sqrt{2}: 1$
  3. $2: 3$
  4. $4: 3$

Solution

The power factor of the circuit $A$ is $\begin{aligned} & \cos \phi_A=\frac{R}{\sqrt{R^2+X_L^2}} \\ & =\frac{R}{\sqrt{R^2+(3 R)^2}}=\frac{1}{\sqrt{10}} . \end{aligned}$ Similarly, the power factor of the circuit $B$ is $\begin{aligned} \cos \phi_B=\frac{R}{\sqrt{R^2+(X_L^2-X_C)^2}} \\ =\frac{R}{\sqrt{R^2+(3 R-R)^2}}=\frac{1}{\sqrt{5}} . \end{aligned}$ $\therefore$ ratio of power factor of the circuit $B$ to the circuit $A$ is $\frac{\cos \phi_B}{\cos \phi_A}=\frac{1 / \sqrt{5}}{1 / \sqrt{10}}=\sqrt{2}$

Asked in: TEST SERIES MHT-CET Full Test 6

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