Two dice are rolled. Then, the probability that the total score is a prime number is
Two dice are rolled. Then, the probability that the total score is a prime number is
$\frac{1}{16}$
$\frac{5}{12}$
$\frac{1}{2}$
$\frac{7}{9}$
Solution
Let two dice are rolled, the total number of outcomes is 36 .
The outcomes when we get a total score as prime number are $(1,1),(1,2),(2,1),(1,4),(2,3)$, $(3,2),(4,1),(1,6),(2,5),(5,2),(3,4),(4,3)$, $(6,1),(5,6),(6,5)$
$P($ total score is a prime number $)=\frac{15}{36}=\frac{5}{12}$