Two dice are rolled simultaneously. The probability that the sum of the two numbers on the dice is a prime number, is

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Aicharya · Accepted Answer

Given that, $A=\{2,3,5,7,11\}$ Required Probability $\begin{aligned} &=P(X=2)+P(X=3)+P(X=5) \ &+P(X=7)+P(X=1 \ &=\frac{1}{36}+\frac{2}{36}+\frac{4}{36}+\frac{6}{36}+\frac{2}{36}=\frac{15}{36}=\frac{5}{12}\end{aligned}$

Two dice are rolled simultaneously. The probability that the sum of the two numbers on the dice is a prime…

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