Two dice are rolled. Probability of getting a sum of $7$ is

Two dice are rolled. Probability of getting a sum of $7$ is
  1. $\dfrac{1}{6}$
  2. $\dfrac{1}{12}$
  3. $\dfrac{6}{36}$
  4. $\dfrac{7}{36}$

Solution

$6$ favourable outcomes out of $36$: $\dfrac{6}{36} = \dfrac{1}{6}$.

Asked in: MH-SSC-9

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