Two dice are rolled. Probability of getting a sum of $7$ is:

Two dice are rolled. Probability of getting a sum of $7$ is:
  1. $\dfrac{1}{12}$
  2. $\dfrac{1}{9}$
  3. $\dfrac{1}{6}$
  4. $\dfrac{7}{36}$

Solution

Total outcomes $= 36$. Favourable: $(1,6),(2,5),(3,4),(4,3),(5,2),(6,1) = 6$. $P = \dfrac{6}{36} = \dfrac{1}{6}$.

Asked in: IMO

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