Two dice are rolled. Probability of getting a sum of $12$ is:

Two dice are rolled. Probability of getting a sum of $12$ is:
  1. $\dfrac{1}{36}$
  2. $\dfrac{1}{18}$
  3. $\dfrac{1}{12}$
  4. $\dfrac{1}{6}$

Solution

Sum $= 12$ only when both dice show $6$: $(6,6)$. $P = \dfrac{1}{36}$.

Asked in: IMO

Practice more DATA HANDLING questions on Aicharya