Two conductors have the same resistance at $0^{\circ} \mathrm{C}$ but their temperature coefficients of…

Two conductors have the same resistance at $0^{\circ} \mathrm{C}$ but their temperature coefficients of resistance are $\alpha_1$ and $\alpha_2$. The respective temperature coefficients of their series and parallel combinations are nearly
  1. $\frac{\alpha_1+\alpha_2}{2}, \alpha_1+\alpha_2$
  2. $\alpha_1+\alpha_2, \frac{\alpha_1+\alpha_2}{2}$
  3. $\alpha_1+\alpha_2, \frac{\alpha_1 \alpha_2}{\alpha_1+\alpha_2}$
  4. $\frac{\alpha_1+\alpha_2}{2}, \frac{\alpha_1+\alpha_2}{2}$

Solution

Let $R_0$ be the initial resistance of both conductors $\therefore \quad$ At temperature $\theta$ their resistance will be, $R_1=R_0\left(1+\alpha_1 \theta\right)$ and $R_2=R_0\left(1+\alpha_2 \theta\right)$ for, series combination, $\mathrm{R}_{\mathrm{s}}=\mathrm{R}_1+\mathrm{R}_2$ $R_{s 0}\left(1+\alpha_s \theta\right)=R_0\left(1+\alpha_1 \theta\right)+R_0\left(1+\alpha_2 \theta\right)$ where $\mathrm{R}_{\mathrm{s} 0}=\mathrm{R}_0+\mathrm{R}_0=2 \mathrm{R}_0$ $\therefore \quad 2 \mathrm{R}_0\left(1+\alpha_s \theta\right)=2 \mathrm{R}_0+\mathrm{R}_0 \theta\left(\alpha_1+\alpha_2\right)$ or $\quad \alpha_s=\frac{\alpha_1+\alpha_2}{2}$ for parallel combination, $ R_p=\frac{R_1 R_2}{R_1+R_2} $ where, $R_{p 0}=\frac{R_0 R_0}{R_0+R_0}=\frac{R_0}{2}$ $\therefore \quad \frac{\mathrm{R}_0}{2}\left(1+\alpha_{\mathrm{p}} \theta\right)=\frac{\mathrm{R}_0^2\left(1+\alpha_1 \theta+\alpha_2 \theta+\alpha_1 \alpha_2 \theta\right)}{\mathrm{R}_0\left(2+\alpha_1 \theta+\alpha_2 \theta\right)}$ as $\alpha_1$ and $\alpha_2$ are small quantities $\therefore \quad \alpha_1 \alpha_2$ is negligible or $\quad \alpha_{\mathrm{p}}=\frac{\alpha_1+\alpha_2}{2+\left(\alpha_1+\alpha_2\right) \theta}=\frac{\alpha_1+\alpha_2}{2}\left[1-\left(\alpha_1+\alpha_2\right) \theta\right]$ as $\left(\alpha_1+\alpha_2\right)^2$ is negligible $\therefore \quad \alpha_p=\frac{\alpha_1+\alpha_2}{2}$

Asked in: JEE Main 2010

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