Two concentric thin circular rings of radii 50 cm and 40 cm , each carry a current of 3.5 A in opposite…
- $11 \times 10^{-7} \mathrm{~T}$
- $22 \times 10^{-7} \mathrm{~T}$
- $17 \times 10^{-7} \mathrm{~T}$
- $8 \times 10^{-7} \mathrm{~T}$
Solution

$\mathrm{r}_1=40 \mathrm{~cm}, \mathrm{r}_2=50 \mathrm{~cm}, \mathrm{I}=3.5 \mathrm{~A}$
The magnitude of magnetic field at the centre O of ring, $\begin{aligned} & B=\frac{\mu_0 I}{2}\left(\frac{1}{r_1}-\frac{1}{r_2}\right) \\ & =\frac{4 \pi \times 10^{-7} \times 3.5}{2}\left(\frac{1}{40}-\frac{1}{50}\right) \times 10^2 \\ & =10.99 \times 10^{-7} \approx 11 \times 10^{-7} \mathrm{~T} \end{aligned}$
Asked in: AP EAMCET 2024 (20 May Shift 2)
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